1468.(Medium)计算税后工资
Salaries 表:
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| company_id | int |
| employee_id | int |
| employee_name | varchar |
| salary | int |
+---------------+---------+
(company_id, employee_id) 是这个表的主键
这个表包括员工的company id, id, name 和 salary
写一条查询 SQL 来查找每个员工的税后工资
每个公司的税率计算依照以下规则
如果这个公司员工最高工资不到 1000 ,税率为 0% 如果这个公司员工最高工资在 1000 到 10000 之间,税率为 24% 如果这个公司员工最高工资大于 10000 ,税率为 49% 按任意顺序返回结果,税后工资结果取整
结果表格式如下例所示:
Salaries 表:
+------------+-------------+---------------+--------+
| company_id | employee_id | employee_name | salary |
+------------+-------------+---------------+--------+
| 1 | 1 | Tony | 2000 |
| 1 | 2 | Pronub | 21300 |
| 1 | 3 | Tyrrox | 10800 |
| 2 | 1 | Pam | 300 |
| 2 | 7 | Bassem | 450 |
| 2 | 9 | Hermione | 700 |
| 3 | 7 | Bocaben | 100 |
| 3 | 2 | Ognjen | 2200 |
| 3 | 13 | Nyancat | 3300 |
| 3 | 15 | Morninngcat | 7777 |
+------------+-------------+---------------+--------+
Result 表:
+------------+-------------+---------------+--------+
| company_id | employee_id | employee_name | salary |
+------------+-------------+---------------+--------+
| 1 | 1 | Tony | 1020 |
| 1 | 2 | Pronub | 10863 |
| 1 | 3 | Tyrrox | 5508 |
| 2 | 1 | Pam | 300 |
| 2 | 7 | Bassem | 450 |
| 2 | 9 | Hermione | 700 |
| 3 | 7 | Bocaben | 76 |
| 3 | 2 | Ognjen | 1672 |
| 3 | 13 | Nyancat | 2508 |
| 3 | 15 | Morninngcat | 5911 |
+------------+-------------+---------------+--------+
对于公司 1 ,最高工资是 21300 ,其每个员工的税率为 49%
对于公司 2 ,最高工资是 700 ,其每个员工税率为 0%
对于公司 3 ,最高工资是 7777 ,其每个员工税率是 24%
税后工资计算 = 工资 - ( 税率 / 100)*工资
对于上述案例,Morninngcat 的税后工资 = 7777 - 7777 * ( 24 / 100) = 7777 - 1866.48 = 5910.52 ,取整为 5911
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/calculate-salaries
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
Solution
with t as
(select company_id,
case when max(salary)<1000 then 0
when max(salary) between 1000 and 10000 then 0.24
else 0.49 end rate
from Salaries
group by company_id)
select s.company_id, s.employee_id, s.employee_name, round(s.salary*(1-t.rate)) salary
from Salaries s, t
where s.company_id = t.company_id
Last updated
Was this helpful?