1571.(Easy)仓库经理
表: Warehouse
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| name | varchar |
| product_id | int |
| units | int |
+--------------+---------+
(name, product_id) 是该表主键.
该表的行包含了每个仓库的所有商品信息.
表: Products
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| product_id | int |
| product_name | varchar |
| Width | int |
| Length | int |
| Height | int |
+---------------+---------+
product_id 是该表主键.
该表的行包含了每件商品以英尺为单位的尺寸(宽度, 长度和高度)信息.
写一个 SQL 查询来报告, 每个仓库的存货量是多少立方英尺.
仓库名 存货量 返回结果没有顺序要求.
查询结果如下例所示.
Warehouse 表:
+------------+--------------+-------------+
| name | product_id | units |
+------------+--------------+-------------+
| LCHouse1 | 1 | 1 |
| LCHouse1 | 2 | 10 |
| LCHouse1 | 3 | 5 |
| LCHouse2 | 1 | 2 |
| LCHouse2 | 2 | 2 |
| LCHouse3 | 4 | 1 |
+------------+--------------+-------------+
Products 表:
+------------+--------------+------------+----------+-----------+
| product_id | product_name | Width | Length | Height |
+------------+--------------+------------+----------+-----------+
| 1 | LC-TV | 5 | 50 | 40 |
| 2 | LC-KeyChain | 5 | 5 | 5 |
| 3 | LC-Phone | 2 | 10 | 10 |
| 4 | LC-T-Shirt | 4 | 10 | 20 |
+------------+--------------+------------+----------+-----------+
Result 表:
+----------------+------------+
| WAREHOUSE_NAME | VOLUME |
+----------------+------------+
| LCHouse1 | 12250 |
| LCHouse2 | 20250 |
| LCHouse3 | 800 |
+----------------+------------+
Id为1的商品(LC-TV)的存货量为 5x50x40 = 10000
Id为2的商品(LC-KeyChain)的存货量为 5x5x5 = 125
Id为3的商品(LC-Phone)的存货量为 2x10x10 = 200
Id为4的商品(LC-T-Shirt)的存货量为 4x10x20 = 800
仓库LCHouse1: 1个单位的LC-TV + 10个单位的LC-KeyChain + 5个单位的LC-Phone.
总存货量为: 1*10000 + 10*125 + 5*200 = 12250 立方英尺
仓库LCHouse2: 2个单位的LC-TV + 2个单位的LC-KeyChain.
总存货量为: 2*10000 + 2*125 = 20250 立方英尺
仓库LCHouse3: 1个单位的LC-T-Shirt.
总存货量为: 1*800 = 800 立方英尺.
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/warehouse-manager
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
Solution
select
name WAREHOUSE_NAME,
sum(units* Width * Length * Height) VOLUME
from Warehouse left join Products using(product_id)
group by 1
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