> For the complete documentation index, see [llms.txt](https://zqt0.gitbook.io/leetcode/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://zqt0.gitbook.io/leetcode/sql/1082.sales-analysis-i.md).

# 1082.(Easy)销售分析 I

产品表：Product

```
+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| product_id   | int     |
| product_name | varchar |
| unit_price   | int     |
+--------------+---------+
product_id 是这个表的主键.
```

销售表：Sales

```
+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| seller_id   | int     |
| product_id  | int     |
| buyer_id    | int     |
| sale_date   | date    |
| quantity    | int     |
| price       | int     |
+------ ------+---------+
这个表没有主键，它可以有重复的行.
product_id 是 Product 表的外键.
```

编写一个 SQL 查询，查询总销售额最高的销售者，如果有并列的，就都展示出来。

查询结果格式如下所示：

```
Product 表：
+------------+--------------+------------+
| product_id | product_name | unit_price |
+------------+--------------+------------+
| 1          | S8           | 1000       |
| 2          | G4           | 800        |
| 3          | iPhone       | 1400       |
+------------+--------------+------------+

Sales 表：
+-----------+------------+----------+------------+----------+-------+
| seller_id | product_id | buyer_id | sale_date  | quantity | price |
+-----------+------------+----------+------------+----------+-------+
| 1         | 1          | 1        | 2019-01-21 | 2        | 2000  |
| 1         | 2          | 2        | 2019-02-17 | 1        | 800   |
| 2         | 2          | 3        | 2019-06-02 | 1        | 800   |
| 3         | 3          | 4        | 2019-05-13 | 2        | 2800  |
+-----------+------------+----------+------------+----------+-------+

Result 表：
+-------------+
| seller_id   |
+-------------+
| 1           |
| 3           |
+-------------+
Id 为 1 和 3 的销售者，销售总金额都为最高的 2800。
```

来源：力扣（LeetCode）

链接：<https://leetcode-cn.com/problems/sales-analysis-i>

著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

## Solution

```sql
select seller_id
from Sales
group by 1
having sum(price) >= all(select sum(price)
                        from Sales
                        group by seller_id)
```