> For the complete documentation index, see [llms.txt](https://zqt0.gitbook.io/leetcode/llms.txt). Markdown versions of documentation pages are available by appending `.md` to page URLs; this page is available as [Markdown](https://zqt0.gitbook.io/leetcode/sql/181.employees-earning-more-than-their-managers.md).

# 181.(Easy)超过经理收入的员工

Employee 表包含所有员工，他们的经理也属于员工。每个员工都有一个 Id，此外还有一列对应员工的经理的 Id。

```
+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+
```

给定 Employee 表，编写一个 SQL 查询，该查询可以获取收入超过他们经理的员工的姓名。在上面的表格中，Joe 是唯一一个收入超过他的经理的员工。

```
+----------+
| Employee |
+----------+
| Joe      |
+----------+
```

来源：力扣（LeetCode）

链接：<https://leetcode-cn.com/problems/employees-earning-more-than-their-managers>

著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

## Solution

```sql
select a.Name Employee
from Employee a left join Employee b on a.ManagerId = b.Id
where a.Salary > b.Salary
```
