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# 197.(Easy)上升的温度

表 Weather

```
+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| recordDate    | date    |
| temperature   | int     |
+---------------+---------+
id 是这个表的主键
该表包含特定日期的温度信息
```

编写一个 SQL 查询，来查找与之前（昨天的）日期相比温度更高的所有日期的 id 。

返回结果 不要求顺序 。

查询结果格式如下例：

```
Weather
+----+------------+-------------+
| id | recordDate | Temperature |
+----+------------+-------------+
| 1  | 2015-01-01 | 10          |
| 2  | 2015-01-02 | 25          |
| 3  | 2015-01-03 | 20          |
| 4  | 2015-01-04 | 30          |
+----+------------+-------------+

Result table:
+----+
| id |
+----+
| 2  |
| 4  |
+----+
2015-01-02 的温度比前一天高（10 -> 25）
2015-01-04 的温度比前一天高（20 -> 30）
```

来源：力扣（LeetCode）

链接：<https://leetcode-cn.com/problems/rising-temperature>

著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。

## Solution

```sql
select w1.id 
from Weather w1 inner join Weather w2 on 
    datediff(w1.recordDate,w2.recordDate) = 1 and 
    w1.Temperature > w2.Temperature
```